Python-Dunder-Underscore

Published on Tue Mar 01 2022

# Python Dunder Underscore Regular Expression # ## Match ## ```python # coding=utf8 # the above tag defines encoding for this document and is for Python 2.x compatibility import re regex = r'^(__version__)(\s?=\s?)+("(.*)")' test_str = "__version__ = \"0.1.1.1\"" matches = re.search(regex, test_str) if matches: print ("Match was found at {start}-{end}: {match}".format(start = matches.start(), end = matches.end(), match = matches.group())) for groupNum in range(0, len(matches.groups())): groupNum = groupNum + 1 print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = matches.start(groupNum), end = matches.end(groupNum), group = matches.group(groupNum))) # Note: for Python 2.7 compatibility, use ur'' to prefix the regex and u"" to prefix the test string and substitution. ``` ## Substitution ## ### Full String Replacement ### ```python # coding=utf8 # the above tag defines encoding for this document and is for Python 2.x compatibility import re regex = r'^(__version__)(\s?=\s?)+("(.*)")' test_str = "__version__ = \"0.1.1.1\"" subst = "[Replacement]" # You can manually specify the number of replacements by changing the 4th argument result = re.sub(regex, subst, test_str, 1) if result: print (result) # Note: for Python 2.7 compatibility, use ur'' to prefix the regex and u"" to prefix the test string and substitution. ``` ### Dunder Replacement ### ```python # coding=utf8 # the above tag defines encoding for this document and is for Python 2.x compatibility import re regex = r'(__version__)(\s?=\s?)+("(.*)")' test_str = "__version__ = \"0.1.1.1\"" subst = "[Dunder-Replacement] \\g<3>" # You can manually specify the number of replacements by changing the 4th argument result = re.sub(regex, subst, test_str, 1) if result: print (result) # Note: for Python 2.7 compatibility, use ur'' to prefix the regex and u"" to prefix the test string and substitution. ``` ### Version Replacement ### ```python # coding=utf8 # the above tag defines encoding for this document and is for Python 2.x compatibility import re regex = r'(__version__)(\s?=\s?)+("(.*)")' test_str = "__version__ = \"0.1.1.1\"" subst = " \\g<1> = [Dunder-Replacement]" # You can manually specify the number of replacements by changing the 4th argument result = re.sub(regex, subst, test_str, 1) if result: print (result) # Note: for Python 2.7 compatibility, use ur'' to prefix the regex and u"" to prefix the test string and substitution. ```

Additional matching regexes for
Python-Dunder-Underscore

Python-Dunder-Underscore

# Python Dunder Underscore Regular Expression # ## Match ## ```python # coding=utf8 # the above tag defines encoding for this document and is for Python 2.x compatibility import re regex = r'^(__version__)(\s?=\s?)+("(.*)")' test_str = "__version__ = \"0.1.1.1\"" matches = re.search(regex, test_str) if matches: print ("Match was found at {start}-{end}: {match}".format(start = matches.start(), end = matches.end(), match = matches.group())) for groupNum in range(0, len(matches.groups())): groupNum = groupNum + 1 print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = matches.start(groupNum), end = matches.end(groupNum), group = matches.group(groupNum))) # Note: for Python 2.7 compatibility, use ur'' to prefix the regex and u"" to prefix the test string and substitution. ``` ## Substitution ## ### Full String Replacement ### ```python # coding=utf8 # the above tag defines encoding for this document and is for Python 2.x compatibility import re regex = r'^(__version__)(\s?=\s?)+("(.*)")' test_str = "__version__ = \"0.1.1.1\"" subst = "[Replacement]" # You can manually specify the number of replacements by changing the 4th argument result = re.sub(regex, subst, test_str, 1) if result: print (result) # Note: for Python 2.7 compatibility, use ur'' to prefix the regex and u"" to prefix the test string and substitution. ``` ### Dunder Replacement ### ```python # coding=utf8 # the above tag defines encoding for this document and is for Python 2.x compatibility import re regex = r'(__version__)(\s?=\s?)+("(.*)")' test_str = "__version__ = \"0.1.1.1\"" subst = "[Dunder-Replacement] \\g<3>" # You can manually specify the number of replacements by changing the 4th argument result = re.sub(regex, subst, test_str, 1) if result: print (result) # Note: for Python 2.7 compatibility, use ur'' to prefix the regex and u"" to prefix the test string and substitution. ``` ### Version Replacement ### ```python # coding=utf8 # the above tag defines encoding for this document and is for Python 2.x compatibility import re regex = r'(__version__)(\s?=\s?)+("(.*)")' test_str = "__version__ = \"0.1.1.1\"" subst = " \\g<1> = [Dunder-Replacement]" # You can manually specify the number of replacements by changing the 4th argument result = re.sub(regex, subst, test_str, 1) if result: print (result) # Note: for Python 2.7 compatibility, use ur'' to prefix the regex and u"" to prefix the test string and substitution. ```

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